I have a trouble proving a trivial array access function (file arr.c):
int get(int* arr, int key)
{
return arr[key];
}
which is translated by clightgen arr.c
to (file arr.v):
...
Definition f_get := {|
fn_return := tint;
fn_callconv := cc_default;
fn_params := ((_arr, (tptr tint)) :: (_key, tint) :: nil);
fn_vars := nil;
fn_temps := nil;
fn_body :=
(Sreturn (Some (Ederef
(Ebinop Oadd (Etempvar _arr (tptr tint))
(Etempvar _key tint) (tptr tint)) tint)))
|}.
...
Here is the proof start (verif_arr.v):
Require Import floyd.proofauto.
Require Import arr.
Local Open Scope logic.
Local Open Scope Z.
Definition get_spec :=
DECLARE _get
WITH sh : share, k : Z, arr : Z->val, vk : val, varr : val
PRE [_key OF tint, _arr OF (tptr tint)]
PROP (0 <= k < 100; forall i, 0 <= i < 100 -> is_int (arr i))
LOCAL (`(eq vk) (eval_id _key);
`(eq varr) (eval_id _arr);
`isptr (eval_id _arr))
SEP (`(array_at tint sh arr
0 100) (eval_id _arr))
POST [tint] `(array_at tint sh arr
0 100 varr) &&
local(`(eq (arr k)) retval).
Definition Vprog : varspecs := nil.
Definition Gprog : funspecs := get_spec :: nil.
Lemma body_get: semax_body Vprog Gprog f_get get_spec.
Proof.
start_function.
name karg _key.
name arrarg _arr.
forward.
After performing the forward
(the last line in verif_arr.v) I've got the following goal:
array_at tint sh arr 0 100 arrarg
|-- !!(False /\ False /\ arr k = Vundef) &&
array_at tint sh arr 0 100 arrarg
Which implies False
, so I can not prove it. However, the c-implementation is trivial, and the proof just started.
Now to the Question:
What is wrong with the spec, why it got to an unprovable goal?
VST version:
Definition svn_rev := "6834P".
Definition release := "1.5".
Definition date := "2014-10-02".
CompCert version: 2.4
Coq version:
The Coq Proof Assistant, version 8.4pl3 (January 2014)
compiled on Jan 19 2014 23:14:16 with OCaml 4.01.0
In "standard" Verifiable-C, memory references cannot occur in expressions except at top level within a load statement:
x = a[e]; or x = *(e.field); (same as x = e->field;)
where e is any expression that does not access memory.
Or, a store statement, a[e1] = e2; or e1->field = e2; where e1 and e2 do not access memory.
A memory reference must not occur within a return statement. You'll have to factor your program as follows:
int x;
x = arr[key];
return x;
and then go ahead with the proof.
We are considering extensions, i.e. "nonstandard" Verifiable C, in which memory references can be nested inside expressions in other contexts; but it is not at all clear that this is a good way to reason about programs. It will be worth the experiment.
The reason you're getting "False" in your precondition is that the expression arr[key] does not type-check as a valid expression, since it contains a memory reference. We need to work on better error-message feedback in such situations.