Check if a given directory contains any directory in python

Question

Essentially, I'm wondering if the top answer given to this question can be implemented in Python. I am reviewing the modules os, os.path, and shutil and I haven't yet been able to find an easy equivalent, though I assume I'm just missing something simple.

More specifically, say I have a directory A, and inside directory A is any other directory. I can call os.walk('path/to/A') and check if dirnames is empty, but I don't want to make the program go through the entire tree rooted at A; i.e. what I'm looking for should stop and return true as soon as it finds a subdirectory.

For clarity, on a directory containing files but no directories an acceptable solution will return False.

Answer 1

maybe you want

def folders_in(path_to_parent):
    for fname in os.listdir(path_to_parent):
        if os.path.isdir(os.path.join(path_to_parent,fname)):
            yield os.path.join(path_to_parent,fname)

print(list(folders_in("/path/to/parent")))

this will return a list of all subdirectories ... if its empty then there are no subdirectories

or in one line

set([os.path.dirname(p) for p in glob.glob("/path/to/parent/*/*")])

although for a subdirectory to be counted with this method it must have some file in it

or manipulating walk

def subfolders(path_to_parent):
     try:
        return next(os.walk(path_to_parent))[1]
     except StopIteration:
        return []