When using i18n_patterns, how to reverse url without language code

Question

I am using i18n_patterns but I want to use reverse to create a link to the page without language in the url (such that the user will be redirected based on cookies and headers and such).

I have tried

from django.utils.translation import activate, deactivate, get_language
current_lang = get_language()
deactivate()
url = reverse(things)
activate(current_lang)

That works for getting other language versions using activate(target_lang), but if I deactivate I just get urls for the default language (/en/account/ but I want /account/).

I already thought getting alternate language versions is overly complicated, but this I cannot manage at all. Any hints? (Without manually stripping LANGUAGE_CODE from the url)

UPDATE: I also tried

from django.core.urlresolvers import get_resolver
get_resolver(None).reverse(*args, **kwargs)

but get NoReverseMatch

Answer 1

I think the easiest way is to let Django resolve the URL with the language prefix and then just remove the language prefix.

You can write the following function:

import re
from django.core.urlresolvers import reverse

def reverse_no_i18n(viewname, *args, **kwargs):
    result = reverse(viewname, *args, **kwargs)
    m = re.match(r'(/[^/]*)(/.*$)', result)
    return m.groups()[1]

Now, anywhere in your code you can do something like this:

from myproject.utils import reverse_no_i18n

def my_view(request):
    return HttpResponseRedirect(reverse_no_i18n('my_view_name'))

You might also want to create a custom {% url %} templatetag which calls your custom function.