Using COALESCE to handle NULL values in PostgreSQL

Question

I have the following query

SELECT  DISTINCT 
     pt.incentive_marketing, 
     pt.incentive_channel, 
     pt.incentive_advertising 
FROM test.pricing pt 
WHERE pt.contract_id = 90000 
group by 1,2,3 
order by pt.incentive_marketing;

The above query returns the o/p as shown in the attached image

However I want to replace all null values by 0 using COALESCE Please let me know how this can be achieved in above SELECT query

Now I further modified the query using coalesce as below

SELECT  
     COALESCE( pt.incentive_marketing, '0' ), 
     COALESCE(pt.incentive_channel,'0'), 
     COALESCE( pt.incentive_advertising,'0') 
FROM test.pricing pt 
WHERE pt.contract_id = 90000 
group by 1,2,3 

the result of which is as attached in image 2.

I still receive one row with blank values

Answer 1

You can use COALESCE in conjunction with NULLIF for a short, efficient solution:

COALESCE( NULLIF(yourField,'') , '0' )

The NULLIF function will return null if yourField is equal to the second value ('' in the example), making the COALESCE function fully working on all cases:

                 QUERY                     |                RESULT 
---------------------------------------------------------------------------------
SELECT COALESCE(NULLIF(null  ,''),'0')     |                 '0'
SELECT COALESCE(NULLIF(''    ,''),'0')     |                 '0'
SELECT COALESCE(NULLIF('foo' ,''),'0')     |                 'foo'