If I assign something like this to variable Res:
Res=Solve[6-5x+x^2==0];
What will do the following line?
Res[[1,1,2]]
or
Res[[2,1,2]]
Let's examine the FullForm
of Res
to see what Res[[1,1,2]]
means:
In[1]:= Res = Solve[6 - 5 x + x^2 == 0]
Out[1]= {{x -> 2}, {x -> 3}}
In[2]:= FullForm[Res]
Out[2]= List[List[Rule[x, 2]], List[Rule[x, 3]]]
Hence:
Res[[1]] = List[Rule[x,2]]
Res[[1,1]] = Rule[x,2]
Res[[1,1,2]] = 2