I have a directory "a" whcih has 5 sub dirs a1 through a5 in it. All that I want is if I gave a "path" as input to a script, I want the list of directories in that path. For instance here if I had said "path=/home/abc/a" the output should be a1 through a5.
The o/p using os.walk is slightly different than what I want..how do I get it?
>>> import os
>>> for dirs in os.walk("."):
... print "Name", dirs
...
Name ('.', ['a1', 'a2', 'a3', 'a4', 'a5'], [])
Name ('./a1', [], [])
Name ('./a2', [], [])
Name ('./a3', [], [])
Name ('./a4', [], [])
Name ('./a5', [], [])
I'm not sure what you're asking for...all the sub directories in that directory? Try this
os.walk("path").next()[1]
Edit: Should have explained a bit. As Chris mentions, os.walk() will return a generator object, and the next() method retrieves the next item from this object. Since this is a 3-tuple consisting of (root, dirs, files) and you only want sub directories, you only need to index into the relevant part.