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pythonxmllxml

lxml (xml python parser) go to next element


Has someone know how to jump to the next element in xml? i.e

<xml>
<node></node>
<text number="2">Text number 2</text>
<text number="3">Text number 3</text>
...
<text number="N">Text number N</text>
...
<node></node>
</xml>

I would like to be able to jump to element with number 3 then iterate few times forward.

element2 = xpath('//text[@number="2"]')
element3 = element2.nextElement()
returns <text number="3">Text number 3</text>
element4 = element3.nextElement() ...

I know that I can find all elements with attribute 'number' then iterate over them but important for me is to be able to go to next element starting from selected (element after) - example is just simplified

Thanks :)


Solution

  • Working examples are a great way to explore. xpath gives you a list of elements that match your query. help on one of those elements tells you what you want to know.

    >>> import lxml.etree
    >>> root=lxml.etree.fromstring("""<xml>
    ... <node></node>
    ... <text number="2">Text number 2</text>
    ... <text number="3">Text number 3</text>
    ... ...
    ... <text number="N">Text number N</text>
    ... ...
    ... <node></node>
    ... </xml>""")
    >>> elements=root.xpath('//text[@number="2"]')
    >>> elements
    [<Element text at 0x7fdd45d04d88>]
    >>> help(elements[0])
    
    ...
    
     |  getnext(...)
     |      getnext(self)
     |      
     |      Returns the following sibling of this element or None.
    
    ...