Equivalent to *args in Swift?

Question

func sumOf(numbers: Int...) -> Int {
    var sum: Int = 0
    for number in numbers {
       sum += number
    }
    return sum
}
sumOf(1, 2, 3) //6

This is sample code taken from the Swift iBook. It finds the sum of any number of arguments.

A python equivalent of this code would be:

def sumOf(*args):
    sum = 0
    for number in args:
        sum += number
    return sum
sumOf(1, 2, 3) #6

In python, *args accepts all variable types, so if I want to do this for whatever reason, I can:

def sumOf(*args):
    sum = ""
    for number in args:
        sum += str(number)
    return sum
sumOf(1, "test", 3) #"1test3"

How do I do this in Swift? How do I create a function that has a variable number of parameters of ANY TYPE? I don't need to do this, but I'd like to know how.

Thanks.

Answer 1

Something like this?

func concatOf(args: Any...) -> String {
    var concat = ""
    for arg in args {
       concat = "\(concat)\(arg)"
    }
    return concat
}