I have the following:
def method(integer)
a = 3+integer
a += 10 if "one"<"another"
end
Can I write it in one line somehow with chaining methods?
Something like a = 3+f += 10 if "one"<"another"
?
Since and
or &&
both use short-circuit evaluation, you could use:
(a = 3+integer) and ("one"<"another") and (a += 10)
It says in 'Using “and” and “or” in Ruby':
and is useful for chaining related operations together until one of them returns nil or false
Another way of thinking about and is as a reversed if statement modifier