This works:
> sprintf('%d', c(1, 1.5))
[1] "1" "1"
and this doesn't:
> sprintf('%d', c(1.5, 1))
Error in sprintf("%d", c(1.5, 1)) :
invalid format '%d'; use format %f, %e, %g or %a for numeric objects
Why?
This is actually really interesting question. To start, %d
stands for integer. The vector argument is recycled if possible but if it is c(1.5, 1)
it will fail when sprintf()
tries to replace %d
with 1.5 (which is not integer).
I thought it might be related to the fact that in R both integer and double are numeric mode, for example:
storage.mode(c(1.5, 1))
# [1] "double"
storage.mode(c(1, 1.5))
# [1] "double"
mode(c(1,1.5))
# [1] "numeric"
mode(c(1.5,1))
# [1] "numeric"
Thus both vectors should be stored as double. More info about vector in R language definition and in the documentation for ? numeric
:
The potential confusion is that R has used mode "numeric" to mean ‘double or integer’"
I might have found the lines in the underlying C code which explain what is going on:
if(TYPEOF(_this) == REALSXP) {
double r = REAL(_this)[0];
if((double)((int) r) == r)
_this = coerceVector(_this, INTSXP);
This code does the following: If the vector type is REALSXP
(which means numeric) then convert first member of vector to double r
. Then cast r
as integer and then double and if bytes are still same convert whole vector as INTSXP
. Importantly, this code only checks the first element of a vector; if that element can be coerced to integer, then the whole vector is coerced, otherwise the code gives an error.
To test this hypothesis one could compile R with a custom sprintf()
where double r = REAL(_this)[0];
is changed to double r = REAL(_this)[1];
and test whether c(1.5, 1)
works now or not.