Want to extract the data between the last occurrence of [] in the following logs.
[11/10/14 9:20:57:133 GMT] 000002d2 EmailAdapterE I Processing Email :: [****][****@hotmail.com][0][1][63][4][4670][0][2014-11-24][12]
[11/10/14 9:20:57:110 GMT] 000002d2 EmailAdapterE I Processing Email :: [****][****@aol.com][0][1][63][1][3286][0][2014-11-24][10]
[11/10/14 9:20:57:088 GMT] 000002d2 EmailAdapterE I Processing Email :: [****][*****@pietrawoodandstone.com][1][1][63][1][3455][2000][2014-11-24][26]
From this i want the values between the last [] in the line.
For example from the above line... i want the following output
12
10
26
Tried awk, cut and sed but no success
awk is your friend:
$ awk -F[][] '{print $(NF-1)}' file
12
10
26
This sets the field separator to either [ or ]. Based on that, the penultimate field contains what you want, so that we print it with $(NF-1).
Note sed can also make it with some regex:
$ sed -r 's/.*\[([0-9]*)\]$/\1/' file
12
10
26
This catches the last block of digits contained within [] and prints it back with \1.
With grep you can also use a look-behind and look-ahead to match what is in between [ and ] + end of line:
$ grep -Po '(?<=\[)[0-9]*(?=]$)' file
12
10
26