Search code examples
phpintvar-dump

If and Else If Progress Bar

Below is a simple progress bar module I'm trying to create.

    <?php
$progress = 3;

if($progress = 2) {
echo "<pre>progress 2";
var_dump($progress);
echo "</pre><br>";
    $progressPrint = "
    <div class='one progressBar'></div>
    <div class='two progressBar'></div>
    ";echo $progressPrint;
}
elseif($progress = 3) {
echo "<pre>progress3";
var_dump($progress);
echo "</pre><br>";
    $progressPrint = "
    <div class='one progressBar'></div>
    <div class='two progressBar'></div>
    <div class='three progressBar'></div>
    ";echo $progressPrint;
}
elseif($progress = 4) {
    $progressPrint = "
    <div class='one progressBar progressBar'></div>
    <div class='two progressBar'></div>
    <div class='three progressBar'></div>
    <div class='four progressBar'></div>
    ";echo $progressPrint;
}
else {
    echo "nothing";
}

?>

The way it is set up for testing is a manual input of the $progress variable. From there I'm testing against that integer. For some reason I can't get it to read to the $progressBar == 3 elseif.

The var dump shows we're sticking in 2 when the variable is clearly 3.

Solution

  • As per OP's wish to close the question and be marked as solved:

    You're assigning with all the if($progress = instead of comparing if($progress ==