Python cannot get url params

Question

I want to get the param of a url that is sent back to the server when the user submits the form. However I get this error AttributeError: 'HTTPServerRequest' object has no attribute 'get'

My url is http://127.0.0.1:8000/reset?key=0OeKkQcSRXiy6yAvtgd9GGv4DhO1t0EYuybjHG5Buzo=

The url string is created as:

keyVal=base64.b64encode(uuid.uuid4().bytes + uuid.uuid4().bytes)
emailLink = 'http://127.0.0.1:8000/reset?key=%s'%keyVal

The emailLink is a used as a link.

I tried to retrieving the value of the param key in the above url as:

class ResetPwdHandler(tornado.web.RequestHandler):       
    def get(self):
        self.render("reset.html")

    def post(self):
        value = self.request.get('key')
        print value

I receive the other form data fine, using self.get_argument(), if I try to use it here then it says 'key' is missing argument.

I see examples that use urlparse but how could you use this to get the param of the url when the form is submitted.

Answer 1

I've never used Tornado or its web framework, but the documentation is quite clear that the request class doesn't define a get method. You are perhaps confusing it with Flask or webapp2. It seems like you can either do self.request.arguments['key'] or self.get_arguments('key').