I want to create a code that will return "true" (if I type in a palindrome regardless of case or if there are special characters in it), and "false" otherwise. The code I have so far works for phrases with no special characters such as commas, apostrophes, spaces, etc.
def is_palindrome(my_str):
my_str= my_str.casefold()
rev_str= reversed(my_str)
if list(my_str) == list(rev_str):
print("True")
else:
print("False")
when I do:
print (is_palindrome("Rats live on no evil star"))
it returns True because it is a palindrome
when I do:
print (is_palindrome("Hello World!"))
it returns False because it is not a palindrome
when I do:
print (is_palindrome("Madam, I'm Adam"))
it returns False. but I want to create a code that considers this a palindrome
You need to filter before testing then:
letters = [c.casefold() for c in my_str if c.isalpha()]
would pick out only the letters and lowercase them, after which you can test of those letters form a palindrome:
return letters == letters[::-1]
This works because str.isalpha()
returns True
only for letters.
Combined into your function:
def is_palindrome(my_str):
letters = [c.casefold() for c in my_str if c.isalpha()]
return letters == letters[::-1]
Demo:
>>> def is_palindrome(my_str):
... letters = [c.casefold() for c in my_str if c.isalpha()]
... return letters == letters[::-1]
...
>>> is_palindrome("Rats live on no evil star")
True
>>> is_palindrome("Hello World!")
False
>>> is_palindrome("Madam, I'm Adam")
True