I use a jquery to change multiply drop-down-menus with one selection. And I use one drop-down-menu to do the change for all the others.
I added diffrent background color to each option. And when I change an option on the drop-down-menu that contral them all that backround color won't be displayed on the other drop-down-menus.
How can I achive this?
Heres the jquery
function addMessage(msg, clear){
if (clear !== null && clear) {
$('#msgs').html("");
}
$('#msgs').append(msg+"<br/>");
}
function onSelectChange(){
var stext = $("#s_make option:selected").val();
addMessage("you selected: " + stext);
switch (stext) {
case "opt_1":
$("#s_score > option[value='xml_multi_01.php']").attr('selected','selected');
break;
case "opt_2":
$("#s_score > option[value='xml_multi_02.php']").attr('selected','selected');
break;
case "opt_3":
$("#s_score > option[value='xml_multi_03.php']").attr('selected','selected');
break;
case "opt_4":
$("#s_score > option[value='xml_multi_04.php']").attr('selected','selected');
break;
}
}
function init(){
addMessage("init()<br/>");
$("#s_make").change(onSelectChange);
}
// keep this if using jQuery
$(document).ready(init);
And heres the html
<select id='s_make' onChange="this.style.backgroundColor=this.options[this.selectedIndex].style.backgroundColor">
<option value='--' style="background: #ffffff;">Change all options to... </option>
<option value='opt_1' style="background: #bfe29c;">Option 1</option>
<option value='opt_2' style="background: #9cc474;">Option 2</option>
<option value='opt_3' style="background: #b6dafb;">Option 3</option>
<option value='opt_4' style="background: #6cace8;">Option 4</option>
</select>
Option 1Option 2Option 3Option 4
Option 1Option 2Option 3Option 4
Take a look at this jsfiddle and you will propably see what I mean: http://jsfiddle.net/mqw9c88d/
There is a number ways of achieving that, for example you can update color of other select
's once you changed your 'main' select:
function onSelectChange(){
$("#s_score").css('backgroundColor', this.style.backgroundColor);
//other code...
}
See partially working JsFiddle (it changes color only of 2nd select because you have same id for 2nd and 3rd selects)