I think my problem may be quite common, but I did not find an answer. Maybe I am looking at this the wrong way!? How can I end up making a legend from this type of matrix:
X =
[4.4200e+09] [ 600] [ 8] 'm2 hard hm (50)'
[4.4200e+09] [ 600] [ 8] 'm3 hard hm (52)'
[4.4200e+09] [ 600] [ 8] 'm2 soft hm (56)'
[4.4200e+09] [ 600] [ 8] 'm3 soft hm (58)'
[4.4200e+09] [ 600] [ 8] 'm2 hard hm (50)'
[4.4200e+09] [ 600] [ 8] 'm3 hard hm (52)'
[4.4200e+09] [ 600] [ 8] 'm2 soft hm (56)'
[4.4200e+09] [ 600] [ 8] 'm3 soft hm (58)'
[4.4200e+09] [1000] [25] 'm3 hard hex (53)'
[4.4200e+09] [1000] [25] 'm3 soft hex (59)'
where the length of the digits may vary, and the number of rows varies to...
class(X)
ans =
cell
When I write legend(X) matlab complaints. I have tried to solve the problem with sprintf using a loop like
sprintf('%d %d %d %s',X{ind,:})
ans =
4420012257 600 8 m2 hard hm (50)
where ind increments, but then I get the problem that the size may vary (some digits are longer)
The data that should be plotted is in two matricies. So I am looking at ending up with something like:
plot(t,y); legend(X)
Appreciate any help!
Given:
X = {[4.4200e+09] [ 600] [ 8] 'm2 hard hm (50)'
[4.4200e+09] [ 600] [ 8] 'm3 hard hm (52)'
[4.4200e+09] [ 600] [ 8] 'm2 soft hm (56)'
[4.4200e+09] [ 600] [ 8] 'm3 soft hm (58)'
[4.4200e+09] [ 600] [ 8] 'm2 hard hm (50)'
[4.4200e+09] [ 600] [ 8] 'm3 hard hm (52)'
[4.4200e+09] [ 600] [ 8] 'm2 soft hm (56)'
[4.4200e+09] [ 600] [ 8] 'm3 soft hm (58)'
[4.4200e+09] [1000] [25] 'm3 hard hex (53)'
[4.4200e+09] [1000] [25] 'm3 soft hex (59)'}
You can use an implicit loop, specifying that the output of each iteration is stored in a cell, i.e. with 'UniformOutput', false (equivalently 'un',0):
X = arrayfun(@(ii) sprintf('%d %d %d %s',X{ii,:}), 1:size(X,1), 'un',0)';
The arrayfun is equivalent to:
nrows = size(X,1);
s = cell(nrows,1);
for ii = 1:nrows
s{ii} = sprintf('%d %d %d %s',X{ii,:});
end