I have a scalar function f(u) defined implicitly as follows:
pow( u, -f(u) ) + pow( u, f(u) ) = u
The function is approximately 1, but evidently not quite so. I am scratching my head for an efficient means of numerically computing values of this function. Any suggestions?
I hope the notation is clear btw, pow( a, b) = a^b is a raised to the power b.
If we write
u = exp( log(u))
and remember that
cosh( x) = (exp(x) + exp(-x))/2
then your equation turns into
cosh( log(u)*f(u)) = u/2
since cosh(x) >= 1 for all real x, there can be no real solution for u<2, while for u>=2
f(u) = acosh( u/2) / log(u)
where acosh is the inverse of cosh.