I've a problem with some lines of code. I try to generate a picture with php and the gd2 librarie.
<?php
header('Content-type: image/jpeg');
$im = imagecreatefromjpeg('profil.jpg');
imagejpeg($im);
imagedestroy($im);?>
This code doesn't work. There's no image displayed, just a message : "this image can't be displayed because there's error" displayed in white on grey background.
The picture is well loaded and "$im" is a resource created with "imagecreatefromjpeg"...
If i remove all lines except header('Content-type: image/jpeg');
, I've got the same problem.
Who can give me the right way ??
Thanks by advance !
Mickael
Working good after creating a new php file where I pasted my code.
I think that my file was corrupt.