I'm trying to add some social share buttons on my blog with Bootstrap, but I'm not getting how to put the URL from the site after the link of the Twitter /share.
This is the code:
<a href="https://twitter.com/share" class="btn btn-social btn-twitter">
<i class="fa fa-twitter"></i> Share on Twitter</i>
</a>
---------- Edited: Now it's half working. I've made a function that open a popup, the link-in-popup:
<a href="http://www.facebook.com/sharer.php?u=" class="btn btn-social btn-facebook link-in-popup">
<i class="fa fa-facebook"></i> Share on Facebook</i>
</a>
But only open the link "https://www.facebook.com/sharer/sharer.php?u", how do I get the url of the page after the "u"? Twitter itself opens the popup with the link, but not facebook. I need something like " <a href="http://www.facebook.com/sharer.php?u=[URLPAGE]"
Now it's working completely!
Here's the code:
<a href="http://www.facebook.com/sharer.php?u=<?php echo(($_SERVER['HTTPS'] ? 'https://' : 'http://').$_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"]); ?>" class="btn btn-social btn-facebook link-in-popup">
<i class="fa fa-facebook"></i> Share on Facebook</i>
</a>
The php gets the current url. I'm just finding out a way to this whole php code turns into a variable. Thank you all!