I enter to browser this link https://google.com.vn; Google redirect to https://www.google.com.vn; I want alert full url redirect. I used this code:
processNewURL: function(aURI) {
var tabIndex = gBrowser.tabContainer.selectedIndex;
var referredFromURI = gBrowser.tabContainer.childNodes[tabIndex].linkedBrowser.webNavigation.referringURI.spec;
alert(referredFromURI);
},
But it always alert https://www.google.com.vn, and I tested with some short link example bit.ly/R9j52J . It isn't ok. Please help me.
this works, i also show 2 methods to get to webNavigation. the second method is just longed winded way to teach other stuff, recommended way is method 1.
var processNewURL = function(e) {
console.log('e:', e);
var win = e.originalTarget.defaultView;
//start - method 1 to get to webNav:
var webNav = win.QueryInterface(Ci.nsIInterfaceRequestor)
.getInterface(Ci.nsIWebNavigation);
var referredFromURI = webNav.referringURI;
//end - method 1
//start - method 2 long winded way:
/*
var domWin = win.QueryInterface(Ci.nsIInterfaceRequestor)
.getInterface(Ci.nsIWebNavigation)
.QueryInterface(Ci.nsIDocShellTreeItem)
.rootTreeItem
.QueryInterface(Ci.nsIInterfaceRequestor)
.getInterface(Ci.nsIDOMWindow);
var tab = domWin.gBrowser._getTabForContentWindow(win);
//console.log('tab:', tab);
var referredFromURI = tab.linkedBrowser.webNavigation.referringURI;
*/
//end - method 2
if (referredFromURI != null) {
win.alert('referred from:' + referredFromURI.spec);
} else {
win.alert('not redirected');
}
}
gBrowser.addEventListener('DOMContentLoaded', processNewURL, false);