I'm trying to print some 64-bit unsigned integers using something like this:
uint64_t x = 0xFFFFFFFFFFFFFFFF;
printf("Value: %016llx \n", x);
and I get this in response:
0000000000000000lx
If I change the formatting string to %016lx I get a compile warning for using the wrong type and it only prints the lower 32 bits:
00000000FFFFFFFF
I've got the -std=c99 string in my compiler options, which should enforce the ll option, right?
For reference, this is the arm-none-eabi-gcc compiler (v4.7.3) that ships with the latest version of Silicon Labs' Simplicity Studio IDE.
Have you tried this ?
#include <stdio.h>
#include <inttypes.h>
int
main(void)
{
uint64_t n = 0x123456789;
printf("n = %#" PRIx64 "\n", n);
return (0);
}
Implementation of printf or scanf depends on libc your're using and may not support long long. Please, check it by printing value of PRIx64 - I guess in your case it will be "lx" instead of "llx".
Pasting a part of inttype.h of ARM toolchain gcc-arm-embedded
/* 64-bit types */
#if __have_long64
#define __PRI64(x) __STRINGIFY(l##x)
#define __SCN64(x) __STRINGIFY(l##x)
#elif __have_longlong64
#define __PRI64(x) __STRINGIFY(ll##x)
#define __SCN64(x) __STRINGIFY(ll##x)
#else
#define __PRI64(x) __STRINGIFY(x)
#define __SCN64(x) __STRINGIFY(x)
#endif
...
#define PRIx64 __PRI64(x)
#define PRIX64 __PRI64(X)