I have a beginner question on the move assigment in c++11. Let say that I have a class A provided with a move assigment operator:
class A
{
public:
A();
~A();
A& operator=(A&&);
...
}
I also have a class B containing a class A object and provided with a move assignment operator
class B
{
public:
B();
~B();
B& operator=(B&&);
...
private:
A Test;
}
What I was thinking is that the B move assignment operator will call the move assignment operator of its member so I tried this method:
B& B::operator=(B&& Other)
{
...
Test = Other.Test;
...
return *this;
}
But this is not working since the move assignment of class A is not called.
Instead I was able to make the program work by using this method:
B& B::operator=(B&& Other)
{
...
Test = std::move(Other.Test);
...
return *this;
}
I do not understand why the first method is not working. I was thinking that since a constructor will call its members constructors the move assignment operator should do the same. Am I wrong or I made a mistake in my code? Can someone explain, thanks!
Other.Test
is not an rvalue expression since it has a name. OTOH std::move(Other.Test)
has the type A
and the value category xvalue (i.e., an rvalue). Thus, it can bind to the move constructor.
(EDIT : Shamelessly copied @dyp's comment. Thanks, @dyp and @KerrekSB.)