iOS: Change black color in UIImage to another color

Question

I have an image with white border and black color filled inside it. I want to just change the black color to another color at runtime. The user will select the color at runtime in HSB format. How can I do that? I tried CGImageCreateWithMaskingColors by taking const float colorMasking[4]={255, 255, 255, 255}; but I am getting a nil CGImageRef everytime. Please help.

- (UIImage*) maskBlackInImage :(UIImage*) image color:(UIColor*)color
{
    const CGFloat colorMasking[4] = { 222, 255, 222, 255 };
    CGImageRef imageRef = CGImageCreateWithMaskingColors(image.CGImage, colorMasking);
    UIImage* imageB = [UIImage imageWithCGImage:imageRef];
    CGImageRelease(imageRef);
    return imageB;

}

I am attaching the image of bulb - Bulb with Black color filled, white border and transparent background

Update:

I was able to fill black color with another color after using the code in the accepted answer. But, I could see a little bit of color on white border. The image doesn't look that sharp. Attaching the output:

Answer 1

Create a category of UIImage class and add the following method

- (UIImage *)imageTintedWithColor:(UIColor *)color
{
     UIImage *image;
     if (color) {
        // Construct new image the same size as this one.
        UIGraphicsBeginImageContextWithOptions([self size], NO, 0.0); // 0.0 for scale means "scale for device's main screen".
        CGRect rect = CGRectZero;
        rect.size = [self size];

        // tint the image
        [self drawInRect:rect];
        [color set];
        UIRectFillUsingBlendMode(rect, kCGBlendModeScreen);

        // restore alpha channel
        [self drawInRect:rect blendMode:kCGBlendModeDestinationIn alpha:1.0f];

        image = UIGraphicsGetImageFromCurrentImageContext();
        UIGraphicsEndImageContext();
    }
    return image;
}