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haskellghcinon-exhaustive-patterns

Haskell: non-exhaustive-patterns


I am training for a test tomorrow to complete my introduction to functional programming but there is one thing I don't understand.

Whenever I have a program like:

test [] = []
test (x:xs) = test (xs)

What he does is that he takes the first element out of the list and continues with the rest. Whenever there is just one left, xs should be [] which in turn should trigger test [] = []. But whenever I run this algorithm I get an error. Exception: <interactive>:20:5-16: Non-exhaustive patterns in function test.

I couldn't find a clear explanation online. Could somebody please send me a link where this is explained clearly or explain it to me?


Solution

  • The code you posted in the question's body does exhaustive pattern matching. However, if you try to enter this definition into ghci, you should use a single let statement:

    Prelude> let test [] = [] ; test (x:xs) = test xs
    

    What you are doing here is incorrect. You are first defining a non-exhaustive function test:

    Prelude> let test [] = []
    

    And then you are defining another non-exhaustive function, also called test, which hides the first one:

    Prelude> let test (x:xs) = test xs