I have an object (called a) which contains an array of two other objects (called b). I am trying to clone that object (a). When i clone the object, i also want to clone the other two objects. However, when i run a code to change the sub-objects(b) in the original object(a) array, it also changes the array with objects(b) in the cloned object(a). How do i prevent this? This is my code:
<?php
class a{
public $b = array();
function __clone(){
foreach($this->b AS $key => $b){
$this->b[$key] = clone $b;
}
}
function addB($name,$b){
$b->setA($this);
$this->b[$name] = $b;
}
}
class b{
public $a;
public $var = 'no';
function execute(){
$this->var = 'yes';
}
function seeB1(){
return $this->a->b['b1']->var;
}
function setA($a){
$this->a = $a;
}
}
$a1 = new a;
$b1 = new b;
$b2 = new b;
$a1->addB('b1',$b1);
$a1->addB('b2',$b2);
//Clones A
$a2 = clone $a1;
$a1->b['b1']->execute();
var_dump($a1->b['b2']->seeB1()); //This should say Yes. It does
var_dump($a2->b['b2']->seeB1()); //This should say No. It says Yes
?>
The output is:
string 'yes' (length=3)
string 'yes' (length=3)
What i want to do with this script is clone A. After i clone A, i run the function execute() of the original b1 to change $var. Then I view original b1 from the original b2. This shows that $var of original b1 has changed, as it should be. However, if I view cloned b1 from cloned b1, it also shows that $var has changed. It shouldnt.
What am i doing wrong?
Regards, Tom.
You can try to replace your __clone function with the following:
function __clone() {
foreach ($this as $key => $value) {
if (is_object($value) || (is_array($value))) {
$this->{$key} = unserialize(serialize($value));
}
}
}
By using the serialize/unserialize method you will definitely avoid changing the original properties of the object.
Tested it and it works fine for simple objects like the ones in your example.