Find a file in a directory using python by partial name

Question

I have a directory with several hundred thousand files in it.

They all follow this format:

datetime_fileid_metadata_collect.txt

A specific example looks like this :

201405052359559_0002230255_35702088_collect88.txt

I am trying to write a script that pulls out and copies individual files when all I provide it is a list of file ids.

For example I have a text document fileids.txt that constains this

fileids.txt
0002230255
0001627237
0001023000

This is the example script I have written so far. file1 result keeps returning []

import os
import re, glob, shutil
base_dir = 'c:/stuff/tub_0_data/'
destination = 'c:/files_goes_here'
os.chdir(base_dir)
text_file = open('c:/stuff/fileids.txt', 'r')
file_ids = text_file.readlines()
#file_ids = [stripped for stripped in (line.strip() for line in text_file.readlines()) if stripped]
for ids in file_ids:
    id1 = ids.rstrip()
    print 'file id = ',str(id1)
    file1 = glob.glob('*' + str(id1) + '*')
    print str(file1)
    if file1 != []:
        shutil.copy(base_dir + file1, destination)

I know I dont fully understand glob or regular expressions yet. What would I put there if I want to find files based off of a specific string of their filename?

EDIT:

glob.glob('*' + stuff '*') 

worked for finding things within the filename. Not removing linespace was the issue.

Answer 1

text_file.readlines() reads the entire line including the trailing '\n'. Try stripping it. The following will strip newlines and remove empties:

file_ids = [line.strip() for line in text_file if not line.isspace()]