Can I fail to deserialize with XmlSerializer in C# if an element is not found?

Question

I am using XmlSerializer to write and read an object to xml in C#. I currently use the attributes XmlElement and XmlIgnore to manipulate the serialization of the object.

If my xml file is missing an xml element that I require, my object still deserializes (xml -> object) just fine. How do I indicate (preferably via Attributes) that a certain field is "required"?

Here is a sample method of what I am using currently:

[XmlElement(ElementName="numberOfWidgets")]
public int NumberThatIsRequired {
    set ...;
    get ...;
}

My ideal solution would be to add something like an XmlRequired attribute.

Also, is there a good reference for what Attributes are available to manipulate the behavior of XmlSerializer?

Answer 1

I've got an answer for the second part: "Attributes that control XML serialization".

Still investigating the first part...

EDIT: I strongly suspect you can't do this through XML deserialization itself. I've just run xsd.exe on a sample schema which includes a required attribute - and it's exactly the same if the attribute is marked as being optional. If there were a way of requiring properties to be set, I'd expect it to be implemented in that case.

I suspect you've basically got to just validate your tree of objects after deserializing it. Sorry about that...