Is there a way to use unix date
to print the number of seconds since epoch?
I'm open to using other standard shell commands if there is a way
(I'm using Solaris, so there isn't date "+"%s"
)
Thanks
Well, since this is a programming site, I would just compile something like:
#include <stdio.h>
#include <time.h>
int main (void) {
printf ("%d\n",time(0));
return 0;
}
:-)