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javascriptphpjqueryajaxjson

SyntaxError: JSON.parse: unexpected character at line 1 column 1 of the JSON data


I've spend over 6 hours to find an exception or a special character to find in my code but I couldn't. I checked every similar messages in here.

I'm sending the form with magnific popup. First I'm using inline popup to open my form than I'm sending all inputs to main.js to validate.

So, I just need a third-eye.

I've got: index.html, register.php, main.js

Here's the code

FORM

JS/AJAX

PHP-register.php

Here goes the error messages

JSON Output json

Chrome Console:

chrome

Firefox console : firefox


What am i missing?


Solution

  • The fact the character is a < make me think you have a PHP error, have you tried echoing all errors.

    Since I don't have your database, I'm going through your code trying to find errors, so far, I've updated your JS file

    $("#register-form").submit(function (event) {
    
        var entrance = $(this).find('input[name="IsValid"]').val();
        var password = $(this).find('input[name="objPassword"]').val();
        var namesurname = $(this).find('input[name="objNameSurname"]').val();
        var email = $(this).find('input[name="objEmail"]').val();
        var gsm = $(this).find('input[name="objGsm"]').val();
        var adres = $(this).find('input[name="objAddress"]').val();
        var termsOk = $(this).find('input[name="objAcceptTerms"]').val();
    
        var formURL = $(this).attr("action");
    
    
        if (request) {
            request.abort(); // cancel if any process on pending
        }
    
        var postData = {
            "objAskGrant": entrance,
            "objPass": password,
            "objNameSurname": namesurname,
            "objEmail": email,
            "objGsm": parseInt(gsm),
            "objAdres": adres,
            "objTerms": termsOk
        };
    
        $.post(formURL,postData,function(data,status){
            console.log("Data: " + data + "\nStatus: " + status);
        });
    
        event.preventDefault();
    });
    

    PHP Edit:

     if (isset($_POST)) {
    
        $fValid = clear($_POST['objAskGrant']);
        $fTerms = clear($_POST['objTerms']);
    
        if ($fValid) {
            $fPass = clear($_POST['objPass']);
            $fNameSurname = clear($_POST['objNameSurname']);
            $fMail = clear($_POST['objEmail']);
            $fGsm = clear(int($_POST['objGsm']));
            $fAddress = clear($_POST['objAdres']);
            $UserIpAddress = "hidden";
            $UserCityLocation = "hidden";
            $UserCountry = "hidden";
    
            $DateTime = new DateTime();
            $result = $date->format('d-m-Y-H:i:s');
            $krr = explode('-', $result);
            $resultDateTime = implode("", $krr);
    
            $data = array('error' => 'Yükleme Sırasında Hata Oluştu');
    
            $kayit = "INSERT INTO tbl_Records(UserNameSurname, UserMail, UserGsm, UserAddress, DateAdded, UserIp, UserCityLocation, UserCountry, IsChecked, GivenPasscode) VALUES ('$fNameSurname', '$fMail', '$fGsm', '$fAddress', '$resultDateTime', '$UserIpAddress', '$UserCityLocation', '$UserCountry', '$fTerms', '$fPass')";
            $retval = mysql_query( $kayit, $conn ); // Update with you connection details
                if ($retval) {
                    $data = array('success' => 'Register Completed', 'postData' => $_POST);
                }
    
            } // valid ends
        }echo json_encode($data);