Countdown loop for a 'raw_input' on the same line in Python

Question

I want to do a countdown loop for a normal raw_input were the normal raw_input don't change, only the numbers (in raw_input).

So, Do you want to try again? [15-1] outputs on one line and the numbers only change.

This is what I have so far and it doesn't work. So how would I do this?

while True:
            for i in range(15,-1,-1):
                con1=raw_input("\n Do you want to try again? " + str(i,))
            if i == 0:
                print "\n Thanks for playing!"
                exit(0)
            elif con1 == "no":
                print "\n Thanks for playing!"
                time.sleep(3)
                exit(0)
            elif con1 == "yes":
                break

Answer 1

Linux answer -- will not work on Windows

Python 3

import select
import sys


def has_input(timeout=0.0):
    return select.select([sys.stdin], [], [], timeout)[0]


def getans(timeout=15):
    i = timeout
    max_num_length = len(str(timeout))
    while i:
        print("\rDo you want to try again? {:{}} ".format(i, max_num_length),
              end="", flush=True)
        i -= 1
        if has_input(1):
            return input()
    print()
    return None

print(getans())

Python 2

import select
import sys


def has_input(timeout=0.0):
    return select.select([sys.stdin], [], [], timeout)[0]


def getans(timeout=15):
    i = timeout
    max_num_length = len(str(timeout))
    while i:
        sys.stdout.write("\rDo you want to try again? {:{}} ".format(i, max_num_length))
        sys.stdout.flush()
        i -= 1
        if has_input(1):
            return raw_input()
    print
    return None

print getans(5)

getans will return None on timeout, or the response otherwise. Theoretically, if a Windows version of has_input could be implemented, this could work on Windows, but I haven't tested that.