I am trying to open a specific view in my Xamarin.Ios-Project via a Web-Url. The url-scheme works fine and i also check the url in the AppDelegate class as shown below:
[Register("AppDelegate")]
public partial class AppDelegate : MvxApplicationDelegate
{
// other methods ...
public override bool OpenUrl(UIApplication application, NSUrl url, string sourceApplication, NSObject annotation)
{
if (url == null) return false;
var uri = new Uri(url.ToString());
if(uri.Host.Equals("myscheme-host"))
{
var param = GetParameters(uri);
// What can i do here?
ShowViewModel<MyViewModel>();
return true;
}
}
}
How can I show my Viewmodel from this point? I tried to set a value in a static class and check it when the next view loads. But when the app is in the background bevore the user clicked the Url-Scheme-Link, no event (ViewDidLoad, ViewWillAppear, ..) will raise.
Any help is appreciated. Thanks a lot
I am using a custom scheme to start an application (something like myscheme-host:xxxx) so what I would write on the OpenUrl is something like this:
public override bool OpenUrl(UIApplication application, NSUrl url, string sourceApplication, NSObject annotation)
{
if (url.AbsoluteString.StartsWith("myscheme-host:"))
{
this.window.RootViewController = new MySchemeViewController();
In your case you would probably create a new view model from the "xxxx" parameters and pass that view model to a view controller (whether that is straight from the code or through a resolver that pairs the view model with a controller).