How to check for one of multiple accepted options in bash?

Question

I am trying to validate the value of an input variable, and prompt the user for valid value, until I get a valid input ('1' or '2'). I've tried:

while option not in 1 2
do :
    read -p "Please choose an option" option
done

How this can be done in bash?

Answer 1

The classical way is:

while ! { test "$option" = 1 || test "$option" = 2; } do ...

but a cleaner way is to use a case statement:

while :; do
    case "$option" in 
    1|2) break ;;
    *) ... ;;
    esac
done