Suppose I have a grid with a container div, like such:
<div class="a">
<div class="a1"></div>
<div class="a2"></div>
<div class="a3"></div>
<div class="a4"></div>
</div>
and the following sass:
@import "susy";
$susy: (
columns: 12,
gutters: 1/4,
);
.a{
background-color: blue;
height: span(12);
@include span(6);
}
Is it possible to then make the inside of a
be its own 2x2 grid? I'd like to place a1
, a2
, a3
, and a4
in each of the corners of a
something like the following:
.a1, .a2, .a3, .a4{
height: span(1);
}
.a1, .a3{
@include span(1);
}
.a2, .a4{
@include span(last 1);
}
.a1{
background-color: green;
}
.a2{
background-color: orange;
}
.a3{
background-color: red;
}
.a4{
background-color: pink;
}
Where I'd expect the top left corner to have a1
, and go clock-wise through a2
, a3
, and a4
.
Yes, a
is currently spanning 6 columns on your main grid, so the simplest might be to make all your a1
-a4
elements span 3 of 6
:
.a1, .a2, .a3, .a4 {
@include span(3 of 6);
}
.a2, .a4{
@include last;
}
But you can also declare any arbitrary context you want:
.a1, .a2, .a3, .a4 {
@include span(1 of 2);
}
.a2, .a4{
@include last;
}
That's not guaranteed to line up with your global grid, but I don't know if you even want that. You can also look at the with-layout
wrapper, if you want a new default grid for a larger block of code.