I am really confused what big O,big theta and big omega represent: best case, worst case and average case or upper bound and lower bound.
If the answer is upper bound and lower bound, then whose upper bound and lower bound? For example let's consider an algorithm. Then does it have three different expressions or rate of growths for best case, lower case and average case and for every case can we find it's big O, theta and omega.
Lastly, we know merge sort via divide and conquer algorithm has a rate of growth or time complexity of n*log(n), then is it the rate of growth of best case or worst case and how do we relate big O, theta and omega to this. please can you explain via a hypothetical expression.
The notations are all about asymptotic growing. If they explain the worst or the average case depends only on what you say it should express.
E.g. quicksort is a randomized algorithm for sorting. Lets say we use it deterministic and always choose the first element in the list as pivot. Then there exists an input of length n (for all n) such that the worst case is O(n²). But on random lists the average case is O(n log n).
So here I used the big O for average and worst case.
Basically this notation is for simplification. If you have an algorithm that does exactly 5n³-4n²-3logn steps you can simply write O(n³) and get rid of all the crap after n³ and also forget about the constants.
You can use big O to get rid of all monomials except for the one with the biggest exponent and all constant factors (constant means they don't grow, but 10100 is also constant)
At the end you get with O(f(n)) a set of functions, that all have the upper bound f(n) (this means g(n) is in O(f(n)), if you can find a constant number c such that g(n) ≤ c⋅f(n))
To make it a little easier:
I have explained that big O means an upper bound but not strict. so n³ is in O(n³), but also n².
So you can think about big O as a "lower equal".
The same way you can do with the others.
Little o is a strict lower: n² is in o(n³), but n³ is not.
Big Omega is a "greater equal": n³ is in Ω(n³) and also n⁴.
The little omega is a strict "greater": n³ is not in ω(n³) but n⁴ is.
And the big Theta is something like "equal" so n³ is in Θ(n³), but neither n² nor n⁴ is.
I hope this helps a little.