I wish to create a zip archive of my "target" directory (${project.build.directory). using the maven-assembly-plugin seems to me like overkill for such a simple task (and a bit complicated - why must I use another file, the assembly descriptor, for such a task) I can't locate the seemingly more simple maven-zip-plugin in the http://repo1.maven.org/maven2 repository.
Any input?
If the bin
predefined assembly descriptor doesn't suit your needs, then you have three options:
Personally, I would just use the maven-assembly-plugin with the following zip.xml
descriptor:
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0 http://maven.apache.org/xsd/assembly-1.1.0.xsd">
<id>bin</id>
<baseDirectory>/</baseDirectory>
<formats>
<format>zip</format>
</formats>
<fileSets>
<fileSet>
<directory>${project.build.directory}</directory>
</fileSet>
</fileSets>
</assembly>
And in your POM:
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.6</version>
<configuration>
<descriptors>
<descriptor>src/main/assembly/zip.xml</descriptor>
</descriptors>
</configuration>
<executions>
<execution>
<id>make-assembly</id> <!-- this is used for inheritance merges -->
<phase>package</phase> <!-- append to the packaging phase. -->
<goals>
<goal>single</goal> <!-- goals == mojos -->
</goals>
</execution>
</executions>
</plugin>