I have some issue related with the filepath in Java.
Take a look at this path (in the real filepath there's no "{}" brackets, and NULL is real null mark):
\\server\directory\64956012.TIF{NULL}64956014.TIF{NULL}64956016.TIF{NULL}64956018.TIF%
is there some easy way to extract these filenames using i.e. Apache Commons? I don't need whole path (prefix) - I need only filenames.
Thank you in advance.
I assume the format is always the same have a first part with path info and ending with %.
String s1 = "\\\\serverdirectory\\64956012.TIF\u000064956014.TIF\u000064956016.TIF\u000064956018.TIF%";
String s2 = s1.substring(s1.lastIndexOf("\\") + 1, s1.length() - 1);
String[] splitted = s2.split("\u0000");
for (int i = 0; i < splitted.length; i++)
System.out.println(splitted[i]);
s2 contains only the list of filenames separated by the null byte (\u0000). The output of this code is:
64956012.TIF
64956014.TIF
64956016.TIF
64956018.TIF