In Python how can I raise a custom exception and do a trace back as well?

Question

I am newbie to python . I know how to raise a **custom exception** in python with a message printed on to the stdout. But when I am dealing with multiple modules and long codes, while raising an exception with a message , can I trace back as well? what I meant as trace back is get the error line , or say the function and module name where the exception happened ?? I know that the message that I am giving out can be modified in such a way that I add more detail information. But I was wondering if there is any inbuilt way of doing this.

Answer 1

You don't have to "generate" a traceback, Python takes care of this when you raise an exception (custom or builtin).

Python 2.7.3 (default, Feb 27 2014, 19:58:35) 
[GCC 4.6.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
pythonrc start
pythonrc done
>>> class MyException(Exception): pass
... 
>>> def foo():
...     raise MyException("Hey")
... 
>>> def bar():
...    print "in bar"
...    foo()
... 
>>> bar()
in bar
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 3, in bar
  File "<stdin>", line 2, in foo
__main__.MyException: Hey
>>>