What is the inverse of this bitwise shift?

Question

The following statement gives me the value 1 (when I print it with %d). How can I do the opposite of this and give it 1 and it returns me 0x1234? Is this possible?

(0x1234 & 0xF000) >> 12

Answer 1

(0x1FFF & 0xF000) >> 12

Will also gives 1. So the answer is no, you cannot go back to the original value