I have been working on this problem for sometime now. I have 3 .txt files containing some stuff to read in and arrange within a multimap,
std::multimap<std::string, std::multimap<int, int>>
but if the key already exists, I increment the value and if the key is unique, I put the value in the map.
The 3 .txt files (labelled "x," "y," and "z") contain this:
"x.txt" contains primary keys:
a a a b b b c c c d d d e e e
"y.txt" contains secondary keys:
1 2 2 3 4 4 5 4 4 2 6 6 6 6 6
and "z.txt," which counts the secondary keys, contains:
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
The desired output is this:
1 : 1
2 : 2
3 : 1
4 : 2
5 : 1
4 : 2
2 : 1
6 : 2
6 : 3
Which states that there is one 1 in a, two 2's in a, one 3 in b, two 4's in b... and so on.
My code (below) incorrectly produces this result:
1 : 1
2 : 1
2 : 1
2 : 1
3 : 1
4 : 1
4 : 1
5 : 1
6 : 1
6 : 1
6 : 1
Here is the code: Any suggestions?
//needed to output your result (print map)
template<typename a, typename b>
void print1(const std::multimap<a, b>& thing){
for (std::multimap<a,b>::const_iterator it = begin(thing); it != thing.end(); it++){
std::cout << it->first << " : " << it->second << std::endl;
}
}
std::ifstream X("x.txt");
std::ifstream Y("y.txt");
std::ifstream Z("z.txt");
typedef std::multimap<int, int> Y_Z;
typedef std::multimap<std::string, Y_Z> X_Y_Z;
typedef std::pair<int, int> pair_y_z;
typedef std::pair<std::string, Y_Z> pair_x_y_z;
Y_Z y_z;
X_Y_Z x_y_z;
std::string x_;
int y_;
int z_;
if (X){
while (X >> x_, Y >> y_, Z >> z_){
if (x_y_z.empty()) {
y_z.insert(pair_y_z(y_, z_));
x_y_z.insert(pair_x_y_z(x_, y_z));
}
else {
X_Y_Z::iterator first_iter = x_y_z.find(x_);
X_Y_Z::iterator last_iter = x_y_z.upper_bound(x_);
if (x_y_z.find(x_) == x_y_z.end()) {
y_z.insert(pair_y_z(y_, z_));
x_y_z.insert(pair_x_y_z(x_, y_z));
}
else{
for (; first_iter != last_iter; first_iter++){
if (x_y_z.find(x_)->second.find(y_) == x_y_z.find(x_)->second.end()){
//no match
y_z.insert(pair_y_z(y_, z_));
x_y_z.insert(pair_x_y_z(x_, y_z));
break;
}
else{
//found match
x_y_z.find(x_)->second.find(y_)->second += z_;
break;
}
}
}
}
}
}
std::cin.get();
print1(y_z);
std::cin.get();
So. It's totally not clear why you are hurting yourself with this complicated data structure. You've got a key with two parts. So let's make the key to your std::map
a std::pair<T1, T2>
.
If we do that, the code becomes incredibly simple.
#include <iostream>
#include <fstream>
#include <utility>
#include <map>
int main() {
std::ifstream X("x.txt");
std::ifstream Y("y.txt");
std::ifstream Z("z.txt");
std::map<std::pair<std::string, int>, int> data;
std::string x_;
int y_;
int z_;
while (X >> x_, Y >> y_, Z >> z_)
data[std::make_pair(x_, y_)] += z_;
for (auto const & element : data)
std::cout << std::get<1>(element.first) << " : " << element.second << "\n";
}
1 : 1
2 : 2
3 : 1
4 : 2
4 : 2
5 : 1
2 : 1
6 : 2
6 : 3
There is one discrepancy between my output and the desired output, but I think it's an error in what you expect.
Your current output expects:
{a, 1} : 1
{a, 2} : 2
{b, 3} : 1
{b, 4} : 2
{c, 5} : 1 <--- note that this key is out of order with the next one. 5 > 4.
{c, 4} : 2
{d, 2} : 1
{d, 6} : 2
{e, 6} : 3
But I'm assuming that the keys should all be sorted properly, which is what my output does.