The output of my code is as follows
load(1).value(1:end) = [0.0100 0.5030 0.7590 1]
load(2).value(1:end) = [0 0 0 0 1]
load(3).value(1:end) = [0 0 0 0 0 0.2000 0.4000]
But I want
load(1).value(1:end) = [0.0100 0.5030 0.7590 1]
load(2).value(1:end) = [1]
load(3).value(1:end) = [.2000 0.4000]
How can I trim the "leading zeroes, that occur from load(2)" away and later concatenate these array's vertically together in xlsx or csv format?
the csv file should contain:'0.0100 0.5030 0.7590 1' in 1st column, '1' in second column and '.2 .4' in third column
If you save those values in a intermediate array you could select the index equal to zero and delete them.
aux=[0.0100 0.5030 0.7590 1]
aux(aux==0)=[];
load(1).value(1:end) = aux;
aux=[0 0 0 0 1]
aux(aux==0)=[];
load(2).value(1:end) = aux;
aux=[0 0 0 0 0 0.2000 0.4000]
aux(aux==0)=[];
load(3).value(1:end) = aux;
For the concatenation, check vertcat(), for vertical concatenation.