This is about the 8-Queens problem. I'm trying to solve the more generic N-Queens problem.
The goal is to make this rule show me all the possible answers. For example:
solution(Sol,4).
X = [2, 4, 1, 3] ;
X = [3, 1, 4, 2] ;
false.
I managed to get all the answers right and everything but for some reason, my code enters an infinite loop after the last solution.
This is what I've written so far:
no_threat(Queen1, Queen2, Dist):-
Queen1=\=Queen2,
Queen1>0, Queen2>0,
Dist=\=Queen2-Queen1,
Dist=\=Queen1-Queen2,!.
queen_safe_aux(_, [], _):- true,!.
queen_safe_aux(Queen, [L|Ls], Dist):-
no_threat(Queen, L, Dist),
Dist2 is Dist+1,
queen_safe_aux(Queen, Ls, Dist2).
queen_safe(Queen, L):- queen_safe_aux(Queen, L, 1).
legal_solution_aux([]):-true,!.
legal_solution_aux([L|Ls]):- queen_safe(L,Ls),legal_solution_aux(Ls).
legal_solution(L):-
length(L, Length),
range(1, Length, Sorted),
permutation(Sorted, L),
legal_solution_aux(L).
solution(L,N):-legal_solution(L),length(L,N1),N1=N.
This is the range rule I used for the solution (it is correct):
range(From, From, [From]):- true, !.
range(From, To, [From|Ls]):- From < To, From2 is From+1, range(From2, To, Ls).
I know this is probably not the best solution but I could use some help understanding what went wrong here.
Here is the relevant program fragment:
solution(L,N):- legal_solution(L), falselength(L,N1),N1=N. legal_solution(L):- length(L, Length), false,range(1, Length, Sorted),permutation(Sorted, L),legal_solution_aux(L).
This fragment (failure-slice) already loops for a query like solution(L,4)
and thus your entire program will loop as well. You need to modify something in the visible part. I'd suggest:
solution(L, N) :-
length(L, N),
legal_solution(L).
Otherwise, you are heavily using cuts which often limit the applicability of declarative debugging techniques. There is no need here.