Search code examples
bashshelltimeshellcode

Shell Script with time windows and a break in between

I can't figure out how I could get that script to work the correct way.

The subscript will run if it is in the timeframe as example 0800 - 1700 and if it is NOT in the pause time 1200 - 1400.

Here is my shellscript.

if [[ "$socket8_timestart" -le "$timenow"  &&  "$timenow" -le "$socket8_timestop" ]] &&
[[ "$timenow" -lt "$socket8_breakstart"  &&  "$socket8_breakstop" -gt "$timenow" ]] ; then
subscript

Could you please help me?

Solution 
  • "$timenow" -lt "$socket8_breakstart"  &&  "$socket8_breakstop" -gt "$timenow"

    this condition give true only before break, not within break (as intended) but also not after break. which is probably the problem you see.

    consider chaniging the logic slightly:

    #!/bin/bash
timenow="1330"
socket8_timestart="900"
socket8_breakstart="1300"
socket8_breakstop="1400"
socket8_timestop="1500"

(( timenow > socket8_timestart &&
   timenow < socket8_timestop
)) && ((
   timenow < socket8_breakstart ||
   timenow > socket8_breakstop
)) && echo "running"

    alternatively, don't look at break as exception, but split the whole interval into two, one pre-break and one post-break. run script if pre-break OR post-break matches.

    Beware of leading zeroes in your times. Pause testing has been put into a seperate clause for easier factoring. There's no need for an extra clause, but may simplify things.