I have a data which can be generated like this:
set.seed(1)
foo <- sample(1:10000,1000)
foo[c(1:100)] <- 1
After this to get the zvalues, which are calculated by scale, I used:
boo<-rollapply(foo,50,scale)
But all the values of boo seems to be NAN.
background info:
z-score = scale = (x - mean)/ std deviation
My first question is why do I get NAN for all the values? For the first 100, I understand that std dev is o . So, I should get Nan only for the first few rows, but I get NAN for all the rows . I do not understand where I am wrong.
Second question is my actual problem.
I want to take a window of 50 elements and get the z-score only for the 25th or mid element of the window.Then I need to rollapply for all the 1000 datapoints.
So , the output will be z-score of elements from 25 to 975 for its respective 50 window size.How can i get this result using rollapply and scale?
1) rollapply
expects FUN
to return a scalar or a vector, not a column matrix. Returning a vector will eliminate the unwanted NaN values:
rollapply(foo , 50, function(x) c(scale(x)))
The result will be a 951x50 matrix.
2) For the second question try this:
rollapply(foo, 50, function(x) (x[25] - mean(x)) / sd(x))
or this:
rollapply(foo, 50, function(x) scale(x)[25])
or this:
rollapply(foo, 50, function(x) c(scale(x)))[, 25]