Make replacements in a string and use an incremented value in each replacement

Question

$pattern = array ('/\[spoiler\]/', "/\[.spoiler\]/");

$replace = array ("<button title=\"Click to show/hide content\" type=\"button\" onclick=\"if(document.getElementById('spoiler') .style.display=='none') {document.getElementById('spoiler') .style.display=''}else{document.getElementById('spoiler') .style.display='none'}\">Pokaż/ukryj</button><div id=\"spoiler\" style=\"display: none;\">", "</div>");

<?php echo preg_replace($pattern, $replace, '[spoiler]awdawdawd[/spoiler] ');

I need to increment the number of the id to be spoiler1, spoiler2 etc. for each replacement.

Answer 1

To solve this with PHP you can use preg_replace_callback instead. See this shortened example:

$counter  = 1;
$replaced = preg_replace_callback('/\[spoiler\]/', 'replace_with_count', '[spoiler]awdawdawd another[spoiler]');
echo $replaced;
# will show: <button id='spoiler1'>Show 1</button>awdawdawd another<button id='spoiler2'>Show 2</button>

/**
 * Replace all occurrence with an incrementing number
 *
 * @param array $matches
 * @return string
 */
function replace_with_count($matches) {
    global $counter;
    $result = "<button id='spoiler{$counter}'>Show {$counter}</button>";
    $counter++;

    return $result;
}