I am developing a Create form in a .Net MVC project. I will create a simple demo for the question as close as i can have for my real business scenario.
I have a person class and few other classes which inherited from it.
public class Person
{
public int Id { get; set; }
[Required]
public string Forename { get; set; }
[Required]
public string Surname { get; set; }
[Required]
public DateTime Dob { get; set; }
}
public class Teacher: Person
{
[Required]
public string Department { get; set; }
}
public class Student: Person
{
[Required]
public string TermAddress { get; set; }
}
If i have a Action method for create as below.
public class PersonController : Controller
{
public ActionResult Create()
{
var personFactory = new PersonFactory();
var p = personFactory.CreatePerson("student");
return View(p);
}
}
public class PersonFactory
{
public object CreatePerson(string type)
{
switch(type)
{
case "teacher":
return new Teacher();
break;
case "student":
return new Student();
break;
default:
return null;
break;
}
}
}
Is it possible to have a view that can handle both cases? In my business case, there are 10+ different types of similar classes and i am wondering if there is a way that i can get around the problem without creating 10+ views. I know i have be strongly typed the view but it's fine. I can have 10+ view models as long as i can use a single view for that. Any alternative suggestions or ways i can get around this kind of problem are welcome. Thanks.
@{
????????????? just an idea .. something like that .. ???????????
var type = "student";
if(type == "stuent")
{
@model WebApplication1.Models.Student
}
else if(type == "teacher")
{
@model WebApplication1.Models.Teacher
}
}
<h2>Create</h2>
@using (Html.BeginForm())
{
@Html.AntiForgeryToken()
<div class="form-horizontal">
@Html.ValidationSummary(true, "", new { @class = "text-danger" })
@Html.EditorForModel()
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-default" />
</div>
</div>
</div>
}
<div>
@Html.ActionLink("Back to List", "Index")
</div>
@section Scripts {
@Scripts.Render("~/bundles/jqueryval")
}
Unfortunately only one @model declaration is allowed in the file, so the logic you are trying to implement is not supported. If you are using just @Html.EditorForModel(), you can use @model WebApplication1.Models.Person and you will get the correct editor form generated.