I have a data frame with a number of columns. I would like to create a new column called “id” that gives a unique id number to each group of identical values in the “sample” column.
Example data:
df <- data.frame(
index = 1:30,
val = c(
14L, 22L, 1L, 25L, 3L, 34L, 35L, 36L, 24L, 35L, 33L, 31L, 30L,
30L, 29L, 28L, 26L, 12L, 41L, 36L, 32L, 37L, 56L, 34L, 23L, 24L,
28L, 22L, 10L, 19L
),
sample = c(
5L, 6L, 6L, 7L, 7L, 7L, 8L, 9L, 10L, 11L, 11L, 12L, 13L, 14L,
14L, 15L, 15L, 15L, 16L, 17L, 18L, 18L, 19L, 19L, 19L, 20L, 21L,
22L, 23L, 23L
)
)
What I would like to end up with:
index val sample id
1 1 14 5 1
2 2 22 6 2
3 3 1 6 2
4 4 25 7 3
5 5 3 7 3
6 6 34 7 3
How about
df2 <- transform(df,id=as.numeric(factor(sample)))
?
I think this (cribbed from Add ID column by group) should be slightly more efficient, although perhaps a little harder to remember:
df3 <- transform(df, id=match(sample, unique(sample)))
all.equal(df2,df3) ## TRUE
If you want to do this in tidyverse:
library(dplyr)
df %>% group_by(sample) %>% mutate(id=cur_group_id())