I am currently using this command,
cal $month $year | sed -n '1,2p'
cal $month $year | sed -n '3,$p' |
sed -n '/'$day'/{s/.*\('$day'.*\)/\1/p; :a; n; p; ba; }'
And it is giving me this output
March 2014
Su Mo Tu We Th Fr Sa
4 5 6 7 8
9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25 26 27 28 29
30 31
How can I get this output?
March 2014
Su Mo Tu We Th Fr Sa
4 5 6 7 8
9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25 26 27 28 29
30 31
FYI: $month $year $day is using the current date.
I am trying to avoid using a set number of spaces because if it was a different day then the numbers would not match up with the spaces.
EDIT: For Jonathan Leffler
Thank you! This is getting really close to the output I am looking for. The sample output you posted is exactly what I am looking for but after trying your code. It gave me this instead.
March 2014
Su Mo Tu We Th Fr Sa
2 3 4 5 Q6 7 8
6 7 8
9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25 26 27 28 29
30 31
How am I able to remove the line with the Q? I assume this is coming from the 2nd s/// you provided
EDIT:
Figure it out, Thank you for your help!
This script works (I think):
year=2014
month=3
day=6
cal $month $year | sed -n -e '
1,2p
3,${/'$day'/{
s/^\(.*\)\('$day'.*\)/\1Q\2/
:blanks
s/^\( *\)[^ Q]/\1 /g
t blanks
s/Q//p
:a
n
p
ba
}
}'
Sample output:
March 2014
Su Mo Tu We Th Fr Sa
6 7 8
9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25 26 27 28 29
30 31
s/// command puts a Q (not part of the output from cal) before the day that you want to keep. :blanks, the s/// and the t blanks replace a string of blanks and a non-blank, non-Q with the string of blanks and another blank, zapping all the non-blank characters before the Q.s/Q//p removes the marker and prints the line.