How can I escape all escape-worthy characters in one line of code?

Question

Based on what I see here (accepted answer), it would seem that I could escape strings by doing this:

string s = "Woolworth's";
string t = Regex.Escape(s);
MessageBox.Show(t);

...but stepping through that, I see no difference between s and t (I hoped I'd see "Woolworth\'s" as the value of t instead of "Woolworth's" for both vars).

I could, I guess, do something like this:

    string s = "Woolworth's";
    s = s.Replace("'", "\'");

...etc., also escaping the following: [, ^, $, ., |, ?, *, +, (, ), and \

...but a "one stop shopping" solution would be preferable.

To be more specific, I need a string entered by a user to be something that is acceptable as a string value in an Android arrays.xml file.

For example, it chokes on this:

<item>Woolworth's</item>

...which needs to be this:

<item>Woolworth\'s</item>

Answer 1

Regex.Escape() only escapes regex reserved characters:

Escapes a minimal set of characters (\, *, +, ?, |, {, [, (,), ^, $,., #, and white space) by replacing them with their escape codes. This instructs the regular expression engine to interpret these characters literally rather than as metacharacters.

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Match/Capture a character class of characters you want to escape (note, some characters have special meanings in character classes and need to be escaped like \ and -):

(['^$.|?*+()\\])

And then replace it with a backslash and a reference to the character you want to escape:

\\1

Demo

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In C#:

string s = "Woolworth's";
Regex rgx = new Regex("(['^$.|?*+()\\\\])");

string t = rgx.Replace(s, "\\$1");
// Woolworth\'s

Demo