Obtain the method and url from an XHR

Question

Basically what the title says, I want to get the URL and HTTP Verb from a xhr. Is this possible?

Answer 1

Not natively, I'm afraid. In prototypable implementations you could write your own prototype:

XMLHttpRequest.prototype.__oldOpen = XMLHttpRequest.prototype.open;
XMLHttpRequest.prototype.verb = "";
XMLHttpRequest.prototype.url  = "";
XMLHttpRequest.prototype.open = function (verb, url, async)
{
    this.verb = verb;
    this.url  = url;
    this.__oldOpen.call(this, verb, url, async); 
}

Don't expect it to work in IE7 and older though.

---

I suppose you could do it by completely recreating the XMLHttpRequest object, but it would take a lot of work to get it right:

var oldXHR = XMLHttpRequest;
function XMLHttpRequest()
{
    var realXHR = new oldXHR();
    this.onreadystatechange = function () {}
    this.open = function (verb, url, async)
    {
        this.verb = verb;
        this.url  = url;
        realXHR.open(verb, url, async);
    {
    this.send = function () { realXHR.send(); }

    // all other properties and methods... 
}

Of course, you have to go to the effort of correctly binding onreadystatechange and setting the status, etc.