The main problem is that I recive a binary number with only 10 bits in use from a SerialPort so I use this to receive the complete data:
byte[] buf = new byte[2];
serialPort.Read(buf, 0, buf.Length);
BitArray bits = new BitArray(buf);
The original idea for convert binary to int was this:
foreach (bool b in bits)
{
if(b){
binary += "1";
}
else{
binary+= "0";
}
}
decimal = Convert.ToInt32(binary, 2);
decimal = decimal >> 6;
binary is obviously a string, that works but I need to know if exists another solution, instead of the previuos code I try with this:
decimal = BitConverter.ToInt16(buf, 0);
But this only read the first 8 bits, I need the other 2 bits missing! If I change ToInt16 for a ToInt32
decimal = BitConverter.ToInt32(buf, 0);
The program stops for a System.ArgumentException: Destination array was not long enough...
What can I do?
You can just shift the values in the bytes so that they match, and put them together. If I got the use of bits right, that would be:
int value = (buf[0] << 2) | (buf[1] >> 6);